Tim Drew Net Worth
By Sarah Jenkins
Timothy Andrew "Tim" Drew (born August 31, 1978) is a former American Major League Baseball player.
| Full Name | Tim Drew |
| Net Worth | $950,000 |
| Date Of Birth | August 31, 1978 |
| Place Of Birth | Valdosta, Georgia, USA |
| Height | 6' 1" (1.85 m) |
| Profession | Baseball player |
| Siblings | J. D. Drew, Stephen Drew |
| Nicknames | Tim Drew, Drew, Tim |
| IMDB | |
| Star Sign | Virgo |
| # | Fact |
|---|---|
| 1 | Brother of J.D. Drew and Stephen Drew. |
